复习2-树上问题
A. 树
- 并查集 + dfs + 离线
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41const int N=1e5+2;
char s[N][2];
int x,y,a[N],b[N],fa[N],f[N];
int n,m,cnt,hd[N],to[N],nxt[N],ans[N];
void add(int x,int y)
{
to[++cnt]=y;
nxt[cnt]=hd[x];
hd[x]=cnt;
}
void dfs(int x,int fat)
{
if(b[x])f[x]=x;
else f[x]=f[fat];
fa[x]=fat;
for(int i=hd[x];i;i=nxt[i])
dfs(to[i],x);
}
int find(int x)
{
return x==f[x]?x:f[x]=find(f[x]);
}
int main()
{
scanf("%d%d",&n,&m);
for(int i=1;i<n;++i)
scanf("%d%d",&x,&y),add(x,y);
for(int i=1;i<=m;++i)
{
scanf("%s%d",s[i],&a[i]);
if(*s[i]=='C')++b[a[i]];
}
++b[1];dfs(1,0);cnt=0;
for(int i=m;i;--i)
{
if(*s[i]=='Q')ans[++cnt]=find(a[i]);
else if(!(--b[a[i]]))f[a[i]]=f[fa[a[i]]];
}
for(int i=cnt;i;--i)
printf("%d\n",ans[i]);
}
B. 集合操作
- 启发式合并
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45const int N = 2e5+100;
int n,m,f[N],siz[N],tag[N];
vector<int> a[N];
int v[N];
inline int find(int x)
{
if(f[x]!=x)return f[x]=find(f[x]);
return f[x];
}
inline void merge(int x,int y)
{
if(siz[x]>siz[y])swap(x,y);
a[y].reserve(siz[x]+siz[y]+1);
for(auto i:a[x])a[y].push_back(i),v[i]+=tag[x]-tag[y];
f[find(x)]=y;
siz[y]+=siz[x];
}
signed main()
{
ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
cin>>n>>m;
for(int i=1;i<=n;i++)f[i]=i,siz[i]=1,a[i].push_back(i);
for(int i=1;i<=n;i++)cin>>v[i];
int op,x,y;
for(int i=1;i<=m;i++)
{
// if(clock()-st>0.45*CLOCKS_PER_SEC)cout<<i<<'\n';
cin>>op;
if(op==1)
{
cin>>x>>y;
if(find(x)!=find(y))merge(find(x),find(y));
}
else if(op==2)
{
cin>>x>>y;
tag[find(x)]+=y;
}
else
{
cin>>x;
cout<<v[x]+tag[find(x)]<<'\n';
}
}
}
C. 梦幻布丁
- 启发式合并
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49int color[1000005], ans;
int fa[1000005];
set<int> pos[1000005];
void merge(int u, int v) {
for (int x : pos[u]) {
ans -= ((color[x - 1] == v) + (color[x + 1] == v));
}
for (int x : pos[u]) {
color[x] = v, pos[v].insert(x);
}
pos[u].clear();
}
int main() {
int n, m;
scanf("%d %d", &n, &m);
for (int i = 1; i <= n; i++) {
int x;
scanf("%d", &x);
fa[x] = x;
color[i] = x;
pos[x].insert(i);
}
ans = n;
for (int i = 1; i <= n; i++) {
if (color[i] == color[i - 1]) {
ans--;
}
}
while (m--) {
int op;
scanf("%d", &op);
if (op == 1) {
int x, y;
scanf("%d %d", &x, &y);
if (fa[x] == fa[y]) {
continue;
}
if (pos[fa[x]].size() > pos[fa[y]].size()) {
swap(fa[x], fa[y]);
}
merge(fa[x], fa[y]);
} else {
printf("%d\n", ans);
}
}
}
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